Electricity2018-10-26T07:32:46+10:00

Maths Made Easy Forums Standard Energy & Mass Electricity

Tagged: ,

  • Author

    Posts

  • AdminAdmin

    Keymaster
    Post count: 582

    A 2400-watt heater is run for 6 hours each day. If electricity is charged at 26.3 c/kWh, what is the cost of running the heater for 8 days, to the nearest cent?

    Find the watts per day: 2400 × 6 = 14 400watts

    Find the watts for 8 days 14 400 × 8 = 115 200

    Change to kW by dividing by 1000 (remember kilo = 1000)

    115 200 ÷ 1000 = 115.2kWh

    Find the cost 115.2 × 26.3 = 3029.76 cents

    divide by 100 to change from cents to dollars

    3029.76 ÷ 100
    = $30.30 (rounded to the nearest cent)

You must be logged in to reply to this topic.

Show Buttons
Hide Buttons