A 2400-watt heater is run for 6 hours each day. If electricity is charged at 26.3 c/kWh, what is the cost of running the heater for 8 days, to the nearest cent?
Find the watts per day: 2400 × 6 = 14 400watts
Find the watts for 8 days 14 400 × 8 = 115 200
Change to kW by dividing by 1000 (remember kilo = 1000)
115 200 ÷ 1000 = 115.2kWh
Find the cost 115.2 × 26.3 = 3029.76 cents
divide by 100 to change from cents to dollars
3029.76 ÷ 100
= $30.30 (rounded to the nearest cent)